Updating one column table another column

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The solution is surprisingly simple, thanks to My SQL: UPDATE xoops_bb_posts_text SET post_text=( REPLACE (post_text, 'morphix.sourceforge.net', ' the string function REPLACE, all items in the post_text column with 'morphix.sourceforge.net' get this substring replaced by 'I was not able, using my SQL 4.1.1, to do this as a subquery: UPDATE Groups LEFT JOIN (SELECT Group Id, MIN(Val Within Group) AS base Val FROM Groups GROUP BY Group Id) AS Grp Sum USING (Group Id) SET Val Within Group=Val Within Group-base Val; Csaba Gabor UPDATE Syntax with "on-line" updating value limitations.I had a problem - a had to update a column "rate" but if the existince or new value is greater then 5 this "5" will be finally value in field.What I'm doing here is copying the information I need from the row where job_id=1 to the row where job_id=6, on the same table.Adam Boyle's commment above was just what I was trying to do, update one table based on a relationship between that table and another.PDF (US Ltr) - 37.8Mb PDF (A4) - 37.9Mb PDF (RPM) - 32.9Mb HTML Download (TGZ) - 8.0Mb HTML Download (Zip) - 8.1Mb HTML Download (RPM) - 6.9Mb Man Pages (TGZ) - 132.9Kb Man Pages (Zip) - 189.5Kb Info (Gzip) - 3.4Mb Info (Zip) - 3.4Mb My SQL Backup and Recovery My SQL Globalization My SQL Information Schema My SQL Installation Guide Security in My SQL Starting and Stopping My SQL My SQL and Linux/Unix My SQL and Windows My SQL and OS X Building My SQL from Source My SQL Restrictions and Limitations My SQL Partitioning My SQL Secure Deployment Guide My SQL Tutorial My SQL Performance Schema My SQL Replication Using the My SQL Yum Repository option as part of a table reference.This option takes a list of one or more partitions or subpartitions (or both).Suppose you have a table where each row is associated with a certain group (For example, orders are associated with the customers placing them) where each item WITHIN the group has a distinct number (For example, each person my have a sequence of competition results - each person, therefore, has a 1st, 2nd, 3rd... If you would like to renumber items within their group so that each has the same baseline (say 0), here is an example way to proceed: Create TEMPORARY Table Groups (Id INTEGER AUTO_INCREMENT PRIMARY KEY, Name VARCHAR(31), Group Id VARCHAR(31), Val Within Group INTEGER); INSERT INTO Groups VALUES (null, "Davy", "Boy", 2); INSERT INTO Groups VALUES (null, "Mary", "Girl", 2); INSERT INTO Groups VALUES (null, "Bill", "Boy", 5); INSERT INTO Groups VALUES (null, "Jill", "Girl", -3); INSERT INTO Groups VALUES (null, "Fred", "Boy", 3);# Find the lowest value for each group CREATE TEMPORARY TABLE Group Sum AS SELECT Group Id, MIN(Val Within Group) AS base Val FROM Groups GROUP BY Group Id;# create an index so my SQL can efficiently match ALTER TABLE Group Sum ADD UNIQUE (Group Id);# finally, make the baseline adjustment UPDATE Groups LEFT JOIN Group Sum USING (Group Id) SET Val Within Group=Val Within Group-base Val; SELECT * FROM Groups;# 1 Davy Boy 0# 2 Mary Girl 5# 3 Bill Boy 3# 4 Jill Girl 0# 5 Fred Boy 1#Each group ("Boy", "Girl") now has a (lowest) Val Within Group entry of 0.Notes: That index addition is necessary because on larger tables my SQL would rather die than figure to (internally) index a single column join.when a row of a subset is lost/deleted/moved away from it, the whole subset will need to be reordered.This can be done similarily : SET @pos=0; UPDATE busstops SET pos = ( SELECT @pos := @pos 1 ) WHERE route = 1 ORDER BY pos ASCChris H (chansel0049) I experienced a weird issue converting from 4 to 5.


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